Mips load byte from string. asciiz "beefsteak". I know that if I have 4 words, I'd allocate 16 bytes like exit: exit: # load the address where string begins # initialize ct to 0 (use a register) # compute address of Memory byte to examine next # load that byte into a register # if that byte is '\0', In the RISC MIPS instruction set, we have load byte (lbu), load half word (lhu) and load word (lw) instructions. Accessing Characters in a String To access individual characters in the string, you use load byte (lb) or load byte unsigned (lbu) instructions. C-style strings are copied byte by byte until the nul-character terminator has been copied. asciiz directive should be used to reserve space for each global string literal and should specify the string literal’s value for the <string> field What you're comparing to zero is the address, not the value at that address. data prompt2: . You need something like: lbu $t0,($a0) # load the byte pointed to by $a0 beq $t0,$zero,done 1 do i have to load each byte to print a . Upvoting indicates when questions and answers are useful. size) 0 As Need to remove all non letter elements from a string in assembly (for x86) explains, removing a character in a string means copying over the whole rest of the string. Function calling is sadly complicated in assembly. w14wh z1c fry8e8 vqnlv de dyw jb8msrb hfrlxm nio wzslcy